Find Z transform of F[K] =Cos(ak) u[k] :
F(z) = Z (cos(ak) u(k) )
= Z ( ½ (ejak+e-jak) u(K) )
= ½ (Z (ejak u(k) ) + Z (e-jak) u(K) )
=½ ( Z/ Z-eja + Z/ Z-e-ja)
= ½ ( Z/ Z-eja * Z-e-ja/
Z-e-ja + Z/ Z-e-ja * Z-e-ja/ Z-e-ja
)
=½ ( Z2- Ze-ja / Z2- Zeja
– Ze-ja +1 + Z2- Zeja
/ Z2- Zeja – Ze-ja +1)
=½ (2Z2 – (Zeja – Ze-ja)
/ Z2- Zeja – Ze-ja +1)
= ½(2Z2 – 2Zcos(a)/ Z2-2Zcos(a) +1
= Z (Z-cos(a)) / Z2-2Zcos(a) +1